# Math Help - Integral by parts

1. ## Integral by parts

Integral from 9 to 16 lny/sqrt(y)

Here's my work and on the parts bolded I asked for help from someone else but Im not sure WHY he did those steps:

∫ ln(y)⋅y^(−½) dy =
2⋅y^(½)⋅ln(y) − ∫ 2⋅y^(½)⋅(1/y) dy
2⋅y^(½)⋅ln(y) − 2⋅∫ y^(−½) dy
2⋅y^(½)⋅ln(y) − 2⋅(2)⋅y^(½) + C
2⋅y^(½)⋅ln(y) − 4⋅y^(½) + C
2⋅y^(½)⋅[ ln(y) − 2 ] + C
2⋅√(y)⋅[ ln(y) − 2 ] + C

Im not sure why and how the 4y1/2 got eliminated/broken up from the problem. Can anyone explain why these two parts happen? I can handle the rest of the problem from here as you just have to plug in the two intervals and subtract them from each other.
Thanks!

2. ## Re: Integral by parts

All he did was factor out a $2y^{\frac{1}{2}}$ from the first two terms and then recall $y^{\frac{1}{2}} = \sqrt{y}$. It was for simplification only

3. ## Re: Integral by parts

Let's see, I'm just gonna go from the first bold line to the line above it:
$2y^{1/2}\cdot (\ln(y)-2)+C=\ln(y)\cdot 2y^{1/2}-2\cdot2y^{1/2} +C = 2y^{1/2}\cdot \ln(y)-4y^{1/2} +C$
and the last bold line is just because by definition $y^{1/2}=\sqrt{y}$.

4. ## Re: Integral by parts

OH! I see now. All he did was factor...wow. I appreciate both of your help!