10 viewed and no reply - does this mean this is correct ? thank you
I have the function y = tan(3x + 6); need to find dy when x=3 and dx=0.03
By the formula dy = f'(x)*dx ;
f'(x)= sec^2(3x+6)(4)dx = (1/cos^2(3x+6))(4)dx, (need to calculate in radians)
so,forf'(3) = (1/cos^2(3x+6)) = (1/cos^2(3(3)+6)) = (1/cos^2(15)) = (1/cos^2(45-30)).... am I on the right track , i'm confused on which identity to apply further
Just give me a hint, I don't need the solution,
Thank you
I realized I did completely wrong, I corrected all the mistakes but I'm confused on which identity to apply further
Just give me a hint, I don't need the solution,
I continued in this way:
f'(3) = (1/cos^2(3x+6)) = (1/cos^2(3(3)+6)) = (1/cos^2(15)) = (1/[(1+cos2(15)/2)]) = (2/(1+cos30)) = {2/[1+ sqrt(3)/2]} = [2/[(2+sqrt(3))/2]] = 4/((2+sqrt(3)),
so, dy = (4/((2+sqrt(3)))(3)(0.03) = 0.36/(2+sqrt(3)) = ... am I correct this time, please, tell me I am