Beginner Implicit differentiation

Here's the problem:

$\displaystyle x^4+x^2y+8y^2=10$, Find y' by implicit differentiation.

I set it up like this by taking the derrivative of both sides:

$\displaystyle \frac{\mathrm{d} y}{\mathrm{d} x}[x^4]+\frac{\mathrm{d} y}{\mathrm{d} x}[x^2y]+\frac{\mathrm{d} y}{\mathrm{d} x}[8y^2]=\frac{\mathrm{d} y}{\mathrm{d} x}[10]$

Giving me:

$\displaystyle 4x^3+2xy+x^2y'+16yy'=0$

then:

$\displaystyle x^2y'+16yy'=4x^3+2xy$

Factor out y':

$\displaystyle y'(x^2+16y)=4x^3+2xy$

divide and the answer:

$\displaystyle y'=\frac{4x^3+2xy}{x^2+16y}$

This answer is wrong though. Can someone help me see where I went wrong? I'm wondering if $\displaystyle {\frac{\mathrm{d} y}{\mathrm{d} x}}{[x^2y]}\neq (2xy+x^2y')$

Thanks in advance!

Re: Beginner Implicit differentiation

Quote:

Originally Posted by

**jjtjp** Here's the problem:

$\displaystyle x^4+x^2y+8y^2=10$, Find y' by implicit differentiation.

I set it up like this by taking the derrivative of both sides:

$\displaystyle \frac{\mathrm{d} y}{\mathrm{d} x}[x^4]+\frac{\mathrm{d} y}{\mathrm{d} x}[x^2y]+\frac{\mathrm{d} y}{\mathrm{d} x}[8y^2]=\frac{\mathrm{d} y}{\mathrm{d} x}[10]$

Giving me:

$\displaystyle 4x^3+2xy+x^2y'+16yy'=0$

then:

$\displaystyle x^2y'+16yy'=4x^3+2xy$ This should be $\displaystyle x^2y'+16yy'=-4x^3-2xy$

Factor out y':

$\displaystyle y'(x^2+16y)=4x^3+2xy$

divide and the answer:

$\displaystyle y'=\frac{4x^3+2xy}{x^2+16y}$

This answer is wrong though. Can someone help me see where I went wrong? I'm wondering if $\displaystyle {\frac{\mathrm{d} y}{\mathrm{d} x}}{[x^2y]}\neq (2xy+x^2y')$

Thanks in advance!

See above.

Re: Beginner Implicit differentiation

Wow..I solved the problem 3 times and missed it every time. How the heck?! Anyways, thank you!

Re: Beginner Implicit differentiation

Quote:

Originally Posted by

**jjtjp** Here's the problem:

$\displaystyle x^4+x^2y+8y^2=10$, Find y' by implicit differentiation.

I set it up like this by taking the derrivative of both sides:

$\displaystyle \frac{\mathrm{d} y}{\mathrm{d} x}[x^4]+\frac{\mathrm{d} y}{\mathrm{d} x}[x^2y]+\frac{\mathrm{d} y}{\mathrm{d} x}[8y^2]=\frac{\mathrm{d} y}{\mathrm{d} x}[10]$

Do NOT write "$\displaystyle \frac{\mathrm{d} y}{\mathrm{d} x}[x^4]$", the "y" should not be there. You mean $\displaystyle \frac{\mathrm{d} x^4}{\mathrm{d} x}$ or $\displaystyle \frac{\mathrm{d} }{\mathrm{d} x}[x^4]$

Quote:

Giving me:

$\displaystyle 4x^3+2xy+x^2y'+16yy'=0$

then: $\displaystyle x^2y'+16yy'=4x^3+2xy$

NO, you have **subtracted** $\displaystyle 4x^3+ 2xy$ from both sides. This should be $\displaystyle x^2y'+ 16yy'= -(4x^3+ 2xy)$ or $\displaystyle x^2y'+ 16yy'= -4x^3- 2xy$

Quote:

Factor out y':

$\displaystyle y'(x^2+16y)=4x^3+2xy$

divide and the answer:

$\displaystyle y'=\frac{4x^3+2xy}{x^2+16y}$

This answer is wrong though. Can someone help me see where I went wrong? I'm wondering if $\displaystyle {\frac{\mathrm{d} y}{\mathrm{d} x}}{[x^2y]}\neq (2xy+x^2y')$

Thanks in advance!

Re: Beginner Implicit differentiation

Thanks for the correction.