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Math Help - NEED HELP having trouble with negative exponents and variables

  1. #1
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    NEED HELP having trouble with negative exponents and variables

    -3((b)^-2)+6=-6 I can find the answer on an online calculator but i would very much like to know how to do find b via step by step
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  2. #2
    Senior Member MacstersUndead's Avatar
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    Re: NEED HELP having trouble with negative exponents and variables

    -3b^{-2}+6=-6

    Use SAMDEB (Subtraction/Addition, Multiplication/Division, Exponents, Brackets, Repeat if necessary after brackets removed)

    In this case
    -3b^{-2}= -12 subtract 6 on both sides
    b^{-2} = 4 divide by -3 on both sides
    b^{2} = \frac{1}{4} Multiply both sides by b^{-2} and divide by 4
    b = \sqrt{\frac{1}{4} Take the square root on both sides (Exponents)
    b = \frac{1}{2} Recall the fact that since the square root is also a power (of \frac{1}{2}) and hence \sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}
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