1. ## Differentiating sec

Hi, would someone please tell me how to differentiate sec^2 x?
I tried it and got (-4sin2x)/(cos2x+1)^2
Not sure if that is right tho
xxx

2. Originally Posted by curlywurlysqurly
Hi, would someone please tell me how to differentiate sec^2 x?
I tried it and got (-4sin2x)/(cos2x+1)^2
Not sure if that is right tho
xxx
differentiate?
Dx[sec^2 x] = 2(sec x)(sec x tan x) = 2(sec^2 x)(tan x)
you just nid to apply chain rule.

3. sorry but i don't understand how you did that!!!
where did the tan x come from???

4. Do you know what chain rule is?

$f(x)=\sec^2x.$

To take its derivative, we use $(u^n)'=nu^{n-1}\cdot u'.$

So, $f'(x)=2\sec x\cdot(\sec x)'.$

Does that make sense?

5. yea thats all fine, but how do u differentiate sec x? is it just a standard result or is there some way to do it?

6. You know that $\sec x=\frac1{\cos x}$

Now $\Big[(\cos x)^{-1}\Big]'=-(\cos x)^{-2}\cdot(\cos x)'.$

So, $\frac{\sin x}{\cos^2x}=\frac1{\cos x}\cdot\frac{\sin x}{\cos x}.$

7. okay thanks i get it now!