Integral from 0 to 1 (1-x)^{9 }
I did u substitution
u=1-x
du=-1dx
du/-1 =dx
get new intervals
1-1=0
1-0=1
-1 integral 1/u^9 du <-- unfortunately wrong
-1 u^{10}/10 interval 1 to 0
-1 (0^{10}/10 - 1^{10}/10)
=1/10
Am I correct?
You certainely noticed that is not defined for x = 1, that means the graph of has a vertical asymptote x = 1. Therefore the definite integral doesn't exist.
EDIT: Sorry, I misunderstood your question completely!
Last edited by earboth; March 3rd 2013 at 10:54 PM.