Originally Posted by
Steelers72 Integral from 0 to 1 (1-x)^{9 }
I did u substitution
u=1-x
du=-1dx
du/-1 =dx
get new intervals
1-1=0
1-0=1
-1 integral 1/u^9 du <-- unfortunately wrong
-1 u^{10}/10 interval 1 to 0
-1 (0^{10}/10 - 1^{10}/10)
=1/10
Am I correct?