Integral from 0 to 1 (1-x)^{9 }

I did u substitution

u=1-x

du=-1dx

du/-1 =dx

get new intervals

1-1=0

1-0=1

-1 integral u^9 du

-1 u^{10}/10 interval 1 to 0

-1 (0^{10}/10 - 1^{10}/10)

=1/10

Am I correct?

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- March 3rd 2013, 10:44 PMSteelers72Definite integral question
Integral from 0 to 1 (1-x)

^{9 }

I did u substitution

u=1-x

du=-1dx

du/-1 =dx

get new intervals

1-1=0

1-0=1

-1 integral u^9 du

-1 u^{10}/10 interval 1 to 0

-1 (0^{10}/10 - 1^{10}/10)

=1/10

Am I correct? - March 3rd 2013, 11:50 PMsbhatnagarRe: Definite integral question

Yes, your answer is correct! - March 3rd 2013, 11:52 PMearbothRe: Definite integral question