Use the difference of cubes formula to reduce each fraction
For the first one we get
This will reduce out with the factor of the numerator and now the function is continuous so you can just evaluate at x=27
Hi there! I am currently in grade 12, studying calculus 30 which is just calculus. I have a question about the above topic posted. One contains roots and I'm not sure exactly how to solve it. Any help would be great!
1) lim ( X^1/3 - 3) / (x - 27)
X-->27
2) lim. (square root of x then minus 2 outside of square root / square root x^3 - 8 ( 8 is not under the root)
x--> 4
Use the difference of cubes formula to reduce each fraction
For the first one we get
This will reduce out with the factor of the numerator and now the function is continuous so you can just evaluate at x=27