What is the range of e^{(sinx)(siny)} and how do you figure it out? Thanks!
Well for starters, we know the exponential function is always positive.
We know that $\displaystyle \displaystyle \begin{align*} -1 \leq \sin{(X)} \leq 1 \end{align*}$ for all $\displaystyle \displaystyle \begin{align*} X \end{align*}$, so that means the product of two sine functions is also going to be bounded between these two values.
Therefore the range of $\displaystyle \displaystyle \begin{align*} e^{\sin{(x)}\sin{(y)}} \end{align*}$ is $\displaystyle \displaystyle \begin{align*} \left[ e^{-1} , e^1 \right] \end{align*}$.
Thanks so much! That's exactly what I was looking for
Btw do you mind clarifying your first sentence? As in, why should you write just (-∞, 0)∪(0, 9) and not x∈(-∞, 0)∪(0, 9)? Thanks again
!!!
EDIT: Or I guess what I mean is, how do you define your variable with interval notation? It seems no one ever says "x" anywhere when they say their answer in interval notatio
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Thanks so much! That's exactly what I was looking for
Btw do you mind clarifying your first sentence? As in, why should you write just (-∞, 0)∪(0, 9) and not x∈(-∞, 0)∪(0, 9)? Thanks again
!!!
EDIT: Or I guess what I mean is, how do you define your variable with interval notation? It seems no one ever says "x" anywhere when they say their answer in interval notatio
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