Let Τ = (t, (1+t)/(t), ((1-t^2)/(t)), t>0, and C=Trace(Τ).

Show that C lies on the plane Γ with equation: x - y + z +1 = 0

I got

T(1) = (1, 2, 0)

Plugged in:

x - y + z +1 = 0

(1-2+0+1) = 0

0=0

Then I sketched the graph x - y + z + 1 = 0 in (x,y,z)

Am I done?