is the time when the derivative is zero, and you found the equation for that. So you solve for t and get . Then you plug in to to get the height at time , which is .
- Hollywood
In our simple model of the fight of a ball, the height
y above the foor at time t is
where g is the acceleration due to gravity and vn is the velocity immediately after the nth bounce.
The maximum height of the ball is reached when dy/dt = 0
Find the time
tmax at which this maximum occurs and the maximum height
ymax that the ball reaches.
I am really not sure how to do this, since I do not know what vn is?
dont know how to work ourt
and