General term of a constant sequence is a(n)=6n^2+12n+k/(3n^2+bn+6).Find a(b+k).

I first put 1 in place of "n" and 2 in place of "n" and made them equal. Then I guessed the result. Is there an easier way?

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- February 24th 2013, 11:02 PMkastamonusequences
General term of a constant sequence is a(n)=6n^2+12n+k/(3n^2+bn+6).Find a(b+k).

I first put 1 in place of "n" and 2 in place of "n" and made them equal. Then I guessed the result. Is there an easier way?