solve x''+9x=cos3t where x(0)=1 and x(pi/2)=-1

here x'(0) is not given and i am unable to use x(pi/2)=-1

please help!!

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- February 24th 2013, 01:20 AMprasumlaplace sum
solve x''+9x=cos3t where x(0)=1 and x(pi/2)=-1

here x'(0) is not given and i am unable to use x(pi/2)=-1

please help!! - February 24th 2013, 10:28 AMBobPRe: laplace sum
If you have to use Laplace Transforms, (there are other methods available), run the calculation through with x'(0) as an unknown constant. When you have your solution for x, substitute t=pi/2, x=-1 to evaluate the constant.