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Math Help - Solve the area of an isosceles triangle with differentials

  1. #1
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    Solve the area of an isosceles triangle with differentials

    An isosceles triangle has equal sides of length 12m. If the angle theta between these sides is increased from 30 to 33 degrees, use differentials to approximate the change in the area of the triangle.

    Any help would be very much appreciated.
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  2. #2
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    Re: Solve the area of an isosceles triangle with differentials

    The area of the triangle will be given by A=\frac{1}{2}12^{2}\sin \theta, where intially \theta=30 degrees.

    If \theta is increased by some small ammount \delta \theta, the increase in area \delta A will be given (approximately) by

    \delta A \approx \frac{dA}{d\theta}\delta \theta.

    (Remember that now, \theta should be measured in radians.)
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