$\displaystyle x=1-y^4$, $\displaystyle x=0$; about the $\displaystyle x=9$

I drew a picture and I turned it as if it was $\displaystyle y=1-x^4$ being rotated about $\displaystyle y=9$ and I made into 2 sections.

So I'd have:

$\displaystyle 2\int_{0}^{1}\left( 2\pi (9-x)\left(1-x^4\right)\right)dx=\frac{412}{15}\pi$

Can someone tell if that's correct. I'm using webassign and I'm on my last try lol