Laplace Inverse of 1 is 1/s or Deta(t) I am confused , can anybody give me confirm answer
Thanks a lot in advance
Surely, you understand the relation between a "Laplace transform" and its inverse? (Or, for that matter, any kind of operation and it inverse!)
Yes, so 1 is the "inverse Laplace transform" of , not 1.
The Laplace transform of [tex]\delta(x)[\tex] is .
Okat, NOW what is the inverse Laplace transform of "1"?