dy/dx=1-0.2y, solve for y when y=0, x=0

This is how I solved it dy/(1-0.2y)=dx <=> -5* (-0.2dy/1-0.2y)=dx

integrating the equation, ln(abs) 1-0.2= x+c/-5

1-0.2y=e^(-x/5+c) <=> 1-0.2y=ce^-x/5

My final equation is y=e^(-x/5)-1/-0.2 after plugging in y=0 and x=0

Is it correct?