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Math Help - Integral question

  1. #1
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    Integral question

    Use the Midpoint Rule with the given value of n to approximate the integral. Round the answer to four decimal places.
    π/2 2 cos5 x dx, n = 4
    0





    the midpoints I calculated to be Pi/16, 3pi/16, 5pi/16, and 7pi/16.

    giving this: (pi/8) ((2 cos(pi/16))^5 + (2 cos^5(3 pi/16))^5 +(2 cos^5(5 pi/6))^5+(2 cos^5(7pi/16))^5

    I calculated this to be 50.2345 , which according to the system is wrong. Where did I go wrong? Thanks for any help!




    Last edited by Steelers72; February 15th 2013 at 08:13 PM.
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  2. #2
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    Re: Integral question

    You made two mistakes I think.

    To get the correct answer:

    1) Set you calculator to radians.

    2) Don't put the 2 in the bracket, in fact don't use the brackets there.

    Try \frac{\pi}{8}\left(2 \cos\left(\frac{\pi}{16}\right)^5+...
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  3. #3
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    Re: Integral question

    Thanks!
    Last edited by Steelers72; February 16th 2013 at 03:45 PM.
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