Thread: Limits problem

For (e) the limit as x approaches 1 for f(x) is undefined, for g(x) it's -1 so how would I add them together?

You don't. If f(x) has no limit at x= a and g(x) has limit -1 (or any real number) at x= a, then f+ g has no limit at x= a.

If you add something that is undefined to something that is defined, the result is undefined.

BTW, I see someone wrote "0" next to (b) and "one" next to (d), but those answers are incorrect.

Oh ok.... Lol yah I wrote them, but I changed them already
I put undefined for (b) and -1 for (d)... That's correct right?

For (f) I know that the limit as x approaches 0 is 2 for f(x), and the limit as x approaches 0 for g(x) is 0
So is this how you put them together????

2(2) + 3(0)
4 + 0 = 4

Originally Posted by asilvester635

For (f) I know that the limit as x approaches 0 is 2 for f(x), and the limit as x approaches 0 for g(x) is 0
So is this how you put them together????

2(2) + 3(0)
4 + 0 = 4

Yes.

And this holds true for (g) also??? Since its undefined when x approaches 1 for f(x) then f(x)g(x) has no limit?????

Yes! "Undefined" means there is no number and you can't do any arithmetic with it!