For (e) the limit as x approaches 1 for f(x) is undefined, for g(x) it's -1 so how would I add them together?
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You don't. If f(x) has no limit at x= a and g(x) has limit -1 (or any real number) at x= a, then f+ g has no limit at x= a.
If you add something that is undefined to something that is defined, the result is undefined. BTW, I see someone wrote "0" next to (b) and "one" next to (d), but those answers are incorrect.
Oh ok.... Lol yah I wrote them, but I changed them already I put undefined for (b) and -1 for (d)... That's correct right?
For (f) I know that the limit as x approaches 0 is 2 for f(x), and the limit as x approaches 0 for g(x) is 0 So is this how you put them together???? 2(2) + 3(0) 4 + 0 = 4
Originally Posted by asilvester635 For (f) I know that the limit as x approaches 0 is 2 for f(x), and the limit as x approaches 0 for g(x) is 0 So is this how you put them together???? 2(2) + 3(0) 4 + 0 = 4 Yes.
And this holds true for (g) also??? Since its undefined when x approaches 1 for f(x) then f(x)g(x) has no limit?????
Yes! "Undefined" means there is no number and you can't do any arithmetic with it!
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