For (e) the limit as x approaches 1 for f(x) is undefined, for g(x) it's -1 so how would I add them together?

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- February 15th 2013, 06:56 AMasilvester635Limits problem
For (e) the limit as x approaches 1 for f(x) is undefined, for g(x) it's -1 so how would I add them together?

- February 15th 2013, 07:13 AMHallsofIvyRe: Limits problem
You

**don't**. If f(x) has no limit at x= a and g(x) has limit -1 (or any real number) at x= a, then f+ g has no limit at x= a. - February 15th 2013, 07:14 AMebainesRe: Limits problem
If you add something that is undefined to something that is defined, the result is undefined.

BTW, I see someone wrote "0" next to (b) and "one" next to (d), but those answers are incorrect. - February 15th 2013, 07:18 AMasilvester635Re: Limits problem
Oh ok.... Lol yah I wrote them, but I changed them already

I put undefined for (b) and -1 for (d)... That's correct right? - February 15th 2013, 07:23 AMasilvester635Re: Limits problem
For (f) I know that the limit as x approaches 0 is 2 for f(x), and the limit as x approaches 0 for g(x) is 0

So is this how you put them together????

2(2) + 3(0)

4 + 0 = 4 - February 15th 2013, 07:46 AMebainesRe: Limits problem
- February 15th 2013, 08:43 AMasilvester635Re: Limits problem
And this holds true for (g) also??? Since its undefined when x approaches 1 for f(x) then f(x)g(x) has no limit?????

- February 15th 2013, 10:12 AMHallsofIvyRe: Limits problem
Yes! "Undefined" means there is no number and you can't do

**any**arithmetic with it!