I can't seem to figure out the following derivative:
y = (3x-3)2(2-x5)3
Here is the work I have done so far..
Let u = 3x-3
Let y = u2
= (3)(2u) = (6(3x-3))
Let u = 2-x5
Let y = u3
= (-5x4)(3u2) = -15x4(2-x5)2
Now I used the Product Rule:
(6(3x-3))(2-x5)3 + (-15x4(2-x5)2)(3x-3)2
Here is the Factoring/Simplifying:
3 (3x-3) (2-x5)2 [2 (2-x5) - 5x4 (3x-3)]
3 (3x-3) (2-x5)2 [4 - 2x5 - 15x5 + 15x4]
3 (3x-3) (2-x5)2 [-17x5 + 15x4 + 4]
The bolded portion above is the answer I am getting. Anyone see anything I did wrong?