What are the critical point(s) of h(x)=(9-4x^2)^(1/2) ?

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- Feb 12th 2013, 05:40 PMspyder12Critical Points
What are the critical point(s) of h(x)=(9-4x^2)^(1/2) ?

- Feb 12th 2013, 05:46 PMProve ItRe: Critical Points
The critical points are where .

- Feb 12th 2013, 05:49 PMspyder12Re: Critical Points
after setting the derivative to 0 I got x=0 is that correct?

- Feb 12th 2013, 06:01 PMProve ItRe: Critical Points
What did you get for the derivative?

- Feb 12th 2013, 06:03 PMspyder12Re: Critical Points
I used my calculator for that I got ( -4x ) / ( -4 ( x^2 - 2.25) ^ (1/2) )

- Feb 12th 2013, 10:54 PMProve ItRe: Critical Points
Well if you were going to do it by hand, do it this way...

Let so that .

Then and

So

Yes, you are correct that when then . What is the value of h when x = 0?