Hey kmalik001.
If you have a complex number z = r*(cos(theta) + i*sin(theta)) then z^n = r^n * (cos(n*theta) + i*sin(n*theta)).
If v = z(1)^6* z(2)^−4
determine |v| and angle(v). Also, obtain v in cartesian form.
where z1= 3 +i
z2 = -5 + 5i
I don't know how to raise a complex power to a power. I have searched all over but nothing online makes sense.
Please help me. Thanks!
So far I have done |(√10)^6 * (5√2)^-4| = .4
If that is correct please explain how to solve for angles.
Okay well for the first z1^6 I got 1000cos(110.58) + isin(-270)
So 2 questions:
Should the angles be in radians?
How am i going to multiply this answer to when I get z2^-4. Because I can not change it to re^jtheta form because the angles in cos and sin are different
The second part of this question asks me to solve for z1^3000. I tried the same method but when I type in 3000 power in calculator it doesn't allow me is there another method I could use. Taylor's method or binomial theorem I always get confused solving