The problem is: Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. $\displaystyle y=1/x^2 $ ,

$\displaystyle y = 0 $, $\displaystyle x=1$,$\displaystyle x=5$ about $\displaystyle y=-3$

This is the image I have (although mine's on paper and it shows the washer's depth decreasing)

I did $\displaystyle V = \pi \int_{1}^{5} (\frac{1}{x^2})^2-(3)^2 dx $

I've fiddled around with that a few times, but I feel like I'm now starting to go in circles. I'm hoping I could get an eyeball so I can see what I'm not visualizing correctly. I know that I need the area between y=0 and y, and I assumed the bounds were x=1 and x=5, so I figured I had enough to take the integral with that information.