how do i integrate this? : t / (t+88) ?? i could rewrite it like this : 1 - (88/t+88) but i dont know how to integrate that. i dont think i can substitude anything.
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let u = t + 88, then, du = dt,
so expression is now (u-88)/u .du, or (1 - 88/u)du
now this is simple to integrate.
dont forget to sub back in after integration
Substitute u = t+88:
t = u-88
du = dt
thank u but i dont get how did u go from INT( 1 - 88/u ) du to u - 88*ln(u) ?
which formula did u use, i cant find it on integral table
factor out 88 so u have 88(int) 1/u which is in is the natural log of u. In tables too. Please thank me
oh i got it u take 88 out of integral
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