how do i integrate this? : t / (t+88) ?? i could rewrite it like this : 1 - (88/t+88) but i dont know how to integrate that. i dont think i can substitude anything.
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let u = t + 88, then, du = dt, so expression is now (u-88)/u .du, or (1 - 88/u)du now this is simple to integrate. dont forget to sub back in after integration
Substitute u = t+88: t = u-88 du = dt $\displaystyle \int \frac {t}{t+88} dt = \int \frac {u-88}{u} du = \int (1 - \frac {88} u) du $ $\displaystyle = u - 88 \ln (u) = t+88-88 \ln (t+88)$
thank u but i dont get how did u go from INT( 1 - 88/u ) du to u - 88*ln(u) ? which formula did u use, i cant find it on integral table
factor out 88 so u have 88(int) 1/u which is in is the natural log of u. In tables too. Please thank me
oh i got it u take 88 out of integral
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