# Thread: please help me with this question. 5 dollars for correct answer!!

1. ## please help me with this question.

Thinking about the shape of the graph (no calulus needed), what is the largest
value of f(x,y) = 1/(1+x^2+y^4)?

2. ## Re: please help me with this question. 5 dollars for correct answer!!

Well this one is easy, is obviously that f(0,0) = 1 is the highest value.
Otherwise if x or y increase in any direction from the origin (positive or negative), f will decrease exponenttialy.

3. ## Re: please help me with this question.

Originally Posted by apatite
Thinking about the shape of the graph (no calulus needed), what is the largest
value of f(x,y) = 1/(1+x^2+y^4)?
If no calculus is needed, then why on earth are you posting in 'calculus'?

4. ## Re: please help me with this question.

Originally Posted by Paze
If no calculus is needed, then why on earth are you posting in 'calculus'?
That thought occurred to me, too.

Assuming x and y are real numbers, x^2 and y^4 are nonnegative, so the largest possible value is clearly f(x,y)=1 at (x,y)=(0,0) as draganicimw observed. One rather trivial correction - f does not decrease exponentially away from the origin; its decrease is only polynomial.

- Hollywood

### thinking about the shape of the graph (no calulus needed), what is the largest

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