please help me with this question.

Thinking about the shape of the graph (no calulus needed), what is the largest

value of f(x,y) = 1/(1+x^2+y^4)?

Re: please help me with this question. 5 dollars for correct answer!!

Well this one is easy, is obviously that f(0,0) = 1 is the highest value.

Otherwise if x or y increase in any direction from the origin (positive or negative), f will decrease exponenttialy.

Re: please help me with this question.

Quote:

Originally Posted by

**apatite** Thinking about the shape of the graph (no calulus needed), what is the largest

value of f(x,y) = 1/(1+x^2+y^4)?

If no calculus is needed, then why on earth are you posting in 'calculus'?

Re: please help me with this question.

Quote:

Originally Posted by

**Paze** If no calculus is needed, then why on earth are you posting in 'calculus'?

That thought occurred to me, too.

Assuming x and y are real numbers, x^2 and y^4 are nonnegative, so the largest possible value is clearly f(x,y)=1 at (x,y)=(0,0) as draganicimw observed. One rather trivial correction - f does not decrease exponentially away from the origin; its decrease is only polynomial.

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