Thread: Finding a slope of tangent line

Hey guys
So what I really need help with is not finding the slope it's how do I combine the square root into the F(4+H) part of the derivative formula ?

Let
The slope of the tangent line to the graph of at the point is .
The equation of the tangent line to the graph of at is for

and
.
Hint: the slope is given by the derivative at , ie.

Just substitute "4 + h" for "x" under the radical.

This question just doesn't seem to be working out... I calculated my derivative as 0 which means a slope of 0 .
?

See the attachment. Try the conjugate in the Newton ratio. Remember x^2 - y^2 = (x - y)(x + y).