Area under the graph using Right and Left end-points

Problem 2: Estimate the area under the graph of *f*(*x*) = 4 cos(*x*) from *x = 0 to **x = **π*/2. (Round the answer to four decimal places.)(a) Use four approximating rectangles and right endpoints.

My work and answer (which is wrong according to the site)

Delta x= Pi/2 / 4 = pi/8

*R4= pi/8 (3.8+3.4+2.5+1.6)*

*R4= 4.4375*

(b) b) Use four approximating rectangles and left endpoints.

*L4= pi/8 f(pi/8) + pi/8 f(pi/4) +pi/8 f(3pi/4)*

L4= pi/8 (4 + 3.9 +3.3 + 2.7)

L4=5.4585

I made a graph so these values are my estimates

Re: Area under the graph using Right and Left end-points

Quote:

Originally Posted by

**Steelers72**

Problem 2: Estimate the area under the graph of *f*(*x*) = 4 cos(*x*) from *x = 0 to **x = **π*/2. (Round the answer to four decimal places.)(a) Use four approximating rectangles and right endpoints.

My work and answer (which is wrong according to the site)

Delta x= Pi/2 / 4 = pi/8

*R4= pi/8 (***3.8**+3.4+2.5+1.6)

*R4= 4.4375*

(b) b) Use four approximating rectangles and left endpoints.

*L4= pi/8 f(pi/8) + pi/8 f(pi/4) +pi/8 f(3pi/4)*

L4= pi/8 (4 + 3.9 +3.3 + 2.7)

L4=5.4585

I made a graph so these values are my estimates

I only checked the value I bolded, and it is wrong.

Re: Area under the graph using Right and Left end-points

Your is correct.

Remember, part (a) instructs you to use **right** end points.

As such,

is the right Riemann approximation with four (evenly spaced) rectangles.

**EDIT: GO RAVENS!! **

Re: Area under the graph using Right and Left end-points

Thanks for your replies. So which values do I multiply the values you gave me by? so it's Pi/8 ( f(pi/8)+f(pi/4)+...)and so on. I'm lost on how to find the values needed (as you saw from 3.8 you bolded. Do I make graphs? Really confused on that.

6. En**oug**h said ;)

Re: Area under the graph using Right and Left end-points

Re: Area under the graph using Right and Left end-points

Thank you! I got 3.1631 as the R4 value.

From the left, how would the values change?

It would still be pi/8 (f(pi/8) + f (pi/4) + f(p(3pi/8) + f(pi/2)) and I know from the left side sum it is an over-estimation as compared to the under-estimation from the right.

thanks again for all of your help.

Re: Area under the graph using Right and Left end-points

Quote:

Originally Posted by

**Steelers72** Thank you! I got 3.1631 as the R4 value.

From the left, how would the values change?

It would still be pi/8 (f(pi/8) + f (pi/4) + f(p(3pi/8) + f(pi/2)) and I know from the left side sum it is an over-estimation as compared to the under-estimation from the right.

thanks again for all of your help.

A LEFT Riemann sum uses LEFT endpoints.

Left Riemann Approximation:

Literally draw the rectangles.

Re: Area under the graph using Right and Left end-points