Hi not sure if this answer is correct. Find derivative with respect to x:

(2x - 3y)^3 = x^2 - y

steps:

[(2x + 3y)^3 + y]^1/2 = x

1/2[(2x + 3y)^3 + y]^-1/2 * u'

u' = 3(2x + 3y)^2 * 5

my answer:

1/2[(2x + 3y)^3 + y]^1/2 * 3(2x + 3y)^2 * 5

correct?