Prove that $\displaystyle \int_{-\infty}^\infty e^{-ix^2}(1-2ix^2)dx=\int_{-\infty}^\infty e^{-ix^2}dx$

Printable View

- Feb 6th 2013, 08:21 AMstrammerImproper integral
Prove that $\displaystyle \int_{-\infty}^\infty e^{-ix^2}(1-2ix^2)dx=\int_{-\infty}^\infty e^{-ix^2}dx$

- Feb 6th 2013, 11:00 AMAZachRe: Improper integral
I think that the first step should be to split the integral at zero?