Hi, I need some help with this problem:
Maximize Revenue given the following: R(x,y)=x(1000-0.1x2)+y(200-0.02y) subject to x>0, y>0, and 8x+3y<2400.
This is what I have so far but I don’t know what to do next. :rolleyes:
Can some one help me please :(
1000-0.3x2=0 --> x = ±√(1000/0.3)
200-0.04y=0 --> y = ±√(200/0.04)
The second of these should be y=200/0.04=5000. Which gives the
Originally Posted by MarianaA
critical points at (57.735,5000) and (-57.735,5000). Neither of these
are in the feasible region.
As the constraints are of strict inequality type there is no point in
the faesible region at which R(x,y) takes a maximal value.
If the constraints were:
x>=0, y>=0, and 8x+3y<=2400,
then the maximum would occur on the boundary of the feasible region, and
one could find it by examining R(x,y) on the boundary.
but it is y = ± not y=200/0.04
Originally Posted by CaptainBlack
and how you get 57.735