Dear All! An area, bordered by curves f(x)=x^2 and g(x)=$\displaystyle \sqrt{x}$ we ROTATE aroudn the x axis ad then we have to calculate volume of the geomethrical body we get. pleaswe, any cute ideas? many thanks!
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$\displaystyle \displaystyle \begin{align*} V = \int_0^1{\pi \left( \sqrt{x} \right)^2 \, dx } - \int_0^1{ \pi \left( x^2 \right)^2 \, dx } \end{align*}$
Well, this is still ingenious!!! Please, how did U get this formula? Many thanks!!!!
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