Find the value of c such that the line y=5/6x+15/2 is tangent to the curve y= c(sqrt x)
I am not sure where to start please help
list after with finding the derivative of c(sqrt x)
If is tangent to , then the slope of the line tangent to is .
To find the point at which is tangent to , we first solve for (in terms of ) in . Plug this -coordinate, which we label , into to determine the -coordinate of the point at which is tangent to , which we call .
Finally, plug the point into and you then should be able to solve for .