Find the value of c such that the line y=5/6x+15/2 is tangent to the curve y= c(sqrt x)

I am not sure where to start please help

list after with finding the derivative of c(sqrt x)

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- Jan 31st 2013, 06:18 PMmathisfun26Finding the vaue of c given an equation of line
Find the value of c such that the line y=5/6x+15/2 is tangent to the curve y= c(sqrt x)

I am not sure where to start please help

list after with finding the derivative of c(sqrt x) - Jan 31st 2013, 08:43 PMchiroRe: Finding the vaue of c given an equation of line
Hey mathisfun26.

Hint: Start off by calculating the derivative (and noting that a tangent line has the form y = mx + b where m is the derivative). - Jan 31st 2013, 08:48 PMabenderRe: Finding the vaue of c given an equation of line

If is tangent to , then the slope of the line tangent to is .

To find the point at which is tangent to , we first solve for (in terms of ) in . Plug this -coordinate, which we label , into to determine the -coordinate of the point at which is tangent to , which we call .

Finally, plug the point into and you then should be able to solve for .