Prove that $\displaystyle \int_0^{\pi/4} d \phi e^{i \phi} e^{-R^2 \exp{(i 2 \phi)}} = 0$
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Hey strammer. Hint: Try using the substitution u = e^(i*theta).
Originally Posted by strammer Prove that $\displaystyle \int_0^{\pi/4} d \phi e^{i \phi} e^{-R^2 \exp{(i 2 \phi)}} = 0$ It is not possible to prove it because it is not true : Another integral
Pardon me. It is only true as R tends to infinity.
Obvious !
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