I've spent an hour tonight and most of last night trying to figure this out, please help!
F'(x) = 3/(sqrt(1-x^2)) , f(1/2)=6
my answer: 3sin^-1(x)+9-3pi/6
Ok this is all my work, please let me know what went wrong Im very perplexed at the moment (my TA said this answer was good but unfortunately web homework site does not like it):
3/sqrt(1-x^2)
= 3 ∫1/sqrt(1-x^2) dx
=3sin^-1x+c
f(1/2)=3sin^-1(1/2)
=3(pi/6)+c=9
c=9-3pi/6
final answer f(x)=3sin^-1*x+9-(3pi/6)