1. ## URGENT: Is this the answer to the anti-derivative??

I've spent an hour tonight and most of last night trying to figure this out, please help!

F'(x) = 3/(sqrt(1-x^2)) , f(1/2)=6

2. ## Re: URGENT: Is this the answer to the anti-derivative??

You have used the formula ∫▒〖1/√(a^2-x^2 ) dx = sin^(-1) (x/a) + C where C is constant. How have you got 9 -3pi/6 pl explain

3. ## Re: URGENT: Is this the answer to the anti-derivative??

Ok this is all my work, please let me know what went wrong Im very perplexed at the moment (my TA said this answer was good but unfortunately web homework site does not like it):

3/sqrt(1-x^2)

= 3 1/sqrt(1-x^2) dx
=3sin^-1x+c

f(1/2)=3sin^-1(1/2)
=3(pi/6)+c=9
c=9-3pi/6

4. ## Re: URGENT: Is this the answer to the anti-derivative??

Didn't you say that f(1/2) = 6, not 9?

Also, is there a better way to write \displaystyle \displaystyle \begin{align*} \frac{3\pi}{6} \end{align*}?

6. ## Re: URGENT: Is this the answer to the anti-derivative??

pi/2 and yeah I think I used a number from another example he gave us. thanks.