I wonder how do you prove that the SUM of N / 2^N (N=1 to infinity) is N / (N-1)^2.
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Originally Posted by maltz how do you prove that the SUM of N / 2^N (N=1 to infinity) is N / (N-1)^2. One does not because .
Ops I am sorry. I wrote the question wrong.
It should be SUM (N / K^N) (N = 1 to infinity, K is a positive integer),
and the result is N/(K-1)^2
What is the formula? Thanks again.
Once again you have written a false statement.
This is true:
Please check the original wording of the problem. . . As written, it makes no sense. Prove: .
If , there would be no on the right side.
If you meant: . , .that makes more sense, . . . . but unfortunately, it is not true.
Yeah I suck... sorry. So it is SUM (N/K^N) = K/(K-1)^2
I am just wondering how you can proof it instead of memorizing a formula.
That would be greatly appreciated.
Multiply by x: .
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