How would i solve these derivatives?

1. y=5sec(pi)x tan(pi)x

2. y=ln(e^(-x^2))

3. y= sin sqrt(x) + sqrt(sin2x)

4. y = arctanx + x/

Printable View

- January 30th 2013, 02:00 PMhcharringtonDerivatives
How would i solve these derivatives?

1. y=5sec(pi)x tan(pi)x

2. y=ln(e^(-x^2))

3. y= sin sqrt(x) + sqrt(sin2x)

4. y = arctanx + x/ - January 30th 2013, 02:33 PMAnonymousUserRe: Derivatives
You need to review the product rule and chain rule as you will be using them both. Do you know what they are?

Second, you need to review the rule for derivatives of trig functions and ln and e. For example .... if y = ln(u) then y' = 1/(u) * u'

Memorize these rules in general and you will be able to apply them now matter what. - January 30th 2013, 03:28 PMHallsofIvyRe: Derivatives
This is written badly. What you have written is the constant "5 sec(pi)tan(pi) x^2" but I suspect you mean 5 sec(pi x)tan(pi x). Do you know the derivative of sec(x)? Do you know the derivative of tan(x)? Do you know the chain rule and product rule?

Quote:

2. y=ln(e^(-x^2))

[quote]3. y= sin sqrt(x) + sqrt(sin2x)[quote]

Do you know the derivative of sin(x), and square root of x? Do you know the chain rule?

Quote:

4. y = arctanx + x/

- January 30th 2013, 03:35 PMAnonymousUserRe: Derivatives