Find the derivative

**crazypocket7** · January 28th 2013, 07:29 PM

Hi guys, Could someone tell me if this is correct?

Find the derrivative of the function:
$(x^2-1)/(2x-3)$
(This is a fraction but i can't figure out the forum codes)

The answer I get after working this out is:
$-2/(2x-3)$

**ibdutt** · January 28th 2013, 08:39 PM

It is simple just use the quotient rule

**VonNemo19** · January 28th 2013, 08:40 PM

Look at it likethis:

Product:

$\frac{dy}{dx}\left[(x^2-1)(2x-3)^{-1}\right]$

$=\overbrace{(x^2-1)(-1)(2x-3)^{-2}(2)}^{\text{first times derivative of second}}\underbrace{+}_{\text{plus}}\overbrace{(2x-3)^{-1}(2x)}^{\text{second times drivative of first}}$

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