K so here's the deal my final answer doesn't match up with my book's answer I get ((xcos)(sin)(sqrt(1+x^2)/sqrt(1+x^2)

the answer is the same except sin isn't there. Does any know what I might have done wrong I used the chain rule. Thanks

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- Jan 26th 2013, 01:11 PMmathisfun26Chain rule of Sin(sqrt(1+x^2)
K so here's the deal my final answer doesn't match up with my book's answer I get ((xcos)(sin)(sqrt(1+x^2)/sqrt(1+x^2)

the answer is the same except sin isn't there. Does any know what I might have done wrong I used the chain rule. Thanks - Jan 26th 2013, 01:16 PMSironRe: Chain rule of Sin(sqrt(1+x^2)
$\displaystyle \frac{d}{dx}\left[\sin\left(\sqrt{1+x^2}\right)\right] = \cos\left(\sqrt{1+x^2}\right)$$\displaystyle \frac{d}{dx}\left(\sqrt{1+x^2}\right)$$\displaystyle =\frac{\cos\left(\sqrt{1+x^2}\right)2x}{2\sqrt{1+x ^2}}$

$\displaystyle =\frac{x\cos\left(\sqrt{1+x^2}\right)}{\sqrt{1+x^2 }}$ - Jan 26th 2013, 01:21 PMPlatoRe: Chain rule of Sin(sqrt(1+x^2)
- Jan 26th 2013, 01:34 PMmathisfun26Re: Chain rule of Sin(sqrt(1+x^2)
My answer is that but with sin I'll post my scratch work in a bit

- Jan 26th 2013, 01:44 PMPlatoRe: Chain rule of Sin(sqrt(1+x^2)
- Jan 26th 2013, 06:54 PMHallsofIvyRe: Chain rule of Sin(sqrt(1+x^2)