Find an antiderivative F(x) with F'(x) = f(x) and F(0)=0 f(x)=5e^x What does the F(0)=0 mean and how do I use that to solve this problem? Any help will be very appreciated!
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Hey kuppina. F(0)=0 means that for a function F(x) if you substitute x = 0 then you get the answer 0. Hint: if F(x) = 5e^x + C = 0 when x = 0, then what is C?
Originally Posted by chiro Hey kuppina. F(0)=0 means that for a function F(x) if you substitute x = 0 then you get the answer 0. Hint: if F(x) = 5e^x + C = 0 when x = 0, then what is C? Hi chiro. Would C be 5? I have to do this all by hand and I want to make sure I get the right answer. Thank you!
Last edited by kuppina; Jan 25th 2013 at 04:50 PM.
If F(0) = 0 then this means that F(0) = 5*e^0 + C = 5 + C = 0. So what does this imply?
Originally Posted by chiro If F(0) = 0 then this means that F(0) = 5*e^0 + C = 5 + C = 0. So what does this imply? -5. Thank you so much!
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