y = x^2 - 2x slope of 2 so the equation slope of the given curve is 2x-2 not sure how to proceed any hints?
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Originally Posted by togo y = x^2 - 2x slope of 2 so the equation slope of the given curve is 2x-2 not sure how to proceed any hints? At what point is it true that $\displaystyle y'=2~?$
when x = 2
Originally Posted by togo when x = 2 At what is the point is the tangent?
alright I am pretty stuck on this one can someone just do it ?
Originally Posted by togo alright I am pretty stuck on this one can someone just do it ? The point is $\displaystyle (2,0)$ the slope is $\displaystyle m=2$ so what is the equation of the tangent?
oh that simple y-0 = 2(x - 2)
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