Hi. Equation for curve:

y = 6x - 2x^2 at (2,4)

My work:

= 6 - 4x

= 6 - 4(2)

= 6 - 8 = -2 = M (slope)

reciprocal: 1/-2

y - y1 = m (x - x1)

y - 4 = -2(x-2)

y - 4 = -2x + 4

y = -2x

but this is wrong? thanks.

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- Jan 24th 2013, 09:06 AMtogoEquation of line normal to curve
Hi. Equation for curve:

y = 6x - 2x^2 at (2,4)

My work:

= 6 - 4x

= 6 - 4(2)

= 6 - 8 = -2 = M (slope)

reciprocal: 1/-2

y - y1 = m (x - x1)

y - 4 = -2(x-2)

y - 4 = -2x + 4

y = -2x

but this is wrong? thanks. - Jan 24th 2013, 10:00 AMAZachRe: Equation of line normal to curve
The normal line is the line perpindicular to the curve, and that requires the negative reciprocal I think. So the slope of the normal line should be just 1/2. You can type the question into WolframAlpha to confirm.

- Jan 24th 2013, 10:32 AMtogoRe: Equation of line normal to curve
got it. thanks

- Jan 24th 2013, 04:26 PMProve ItRe: Equation of line normal to curve