x G(x)=∫ t((3t^2+4)^1/2)dt 4 Use the Fundamental Theorem of Calculus to find an algebraic expression for G(x)
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Originally Posted by irock3337 x G(x)=∫ t((3t^2+4)^1/2)dt 4 Use the Fundamental Theorem of Calculus to find an algebraic expression for G(x) What is the derivative of
t(3t^2+4)^2 or is it t(3t^2+4)^1/2
Originally Posted by irock3337 t(3t^2+4)^2 or is it t(3t^2+4)^1/2 It is
So then would I just plug x and 4 into the equation and subtract them from one another to get the answer?
Originally Posted by irock3337 x G(x)=∫ t((3t^2+4)^1/2)dt 4 Use the Fundamental Theorem of Calculus to find an algebraic expression for G(x) If you were going to integrate this directly, first rewrite this integral as and then use a substitution , noting that when and when , and the integral becomes
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