# Math Help - Implicit Differentiation

1. ## Implicit Differentiation

I don't really understand how to do this but I tried to do a problem. Here's my work.

The problem is $2x^3 + x^2 y - x y^3 = 2$

sorry I put up the work to another problem here's the real work:

$2x^3 + (2xy + x^2 y') - (y^3 + y') = 0$

I moved everything except y' to one side and I got this:

$y' = \frac {-2x^3 - 2xy + y^3}{x^2 - 1}$

I have a feeling that I messed up somewhere but I don't know where since I do not fully understand Implicity Differentiation.

2. Originally Posted by FalconPUNCH!
The problem is $2x^3 + x^2 y - x y^3 = 2$
$6x^2+(x^2y)'-(xy^3)'=0$

Product Rule.

3. Originally Posted by Krizalid
$6x^2+(x^2y)'-(xy^3)'=0$

Product Rule.
Not sure if it's right

$y' = \frac {-6x^2 - 2xy + y^3}{x^2 - xy}$

4. sorry I was looking at another problem's work. I put up the work I did for this problem.

5. Here's what I got:

$y' = \frac {-2x^3 - 2xy + y^3}{x^2 - 1}$