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Math Help - Solving limits with free fall

  1. #1
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    Solving limits with free fall

    Hello,

    Just started calculus. I am fairly comfortable with limit problems in what has been given to us, but I'm thoroughly lost when given a problem like this.

    Any help would be appreciated, thanks.
    Attached Thumbnails Attached Thumbnails Solving limits with free fall-calc-limit-freefall.jpg  
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  2. #2
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    Re: Solving limits with free fall

    When you replace s(a) and s(t) with -4.9a^2+200 and -4.9t^2+200, you get a lot of cancellation. Remember the identity x^2-y^2=(x+y)(x-y).

    They're getting you ready for derivatives - the limit you are calculating is just the derivative of s(t) at a.

    - Hollywood
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  3. #3
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    Re: Solving limits with free fall

    So s(a) and s(t) are the exact same? Why do they have different letters then?
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  4. #4
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    Re: Solving limits with free fall

    No, s(a)=-4.9a^2+200 and s(t)=-4.9t^2+200. So when you plug them in, 200 cancels and you can factor out -4.9, giving \frac{a^2-t^2}{a-t}.

    - Hollywood
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