When t=0, dy/dx = -1
(x,y)=(0,0)
Now use
y=-x
Now, it's easy to find the normal.
Hi again;
I have been given the following questions:
now this is what I have done so far:Code:Find the equation of the (i) tangent and (ii) normal lines to the curve given parametrically by x = t2 + t, y = t2 − t at the point corresponding to t = 0.
dx/dt = 2t
dy/dt = 2t
THEREFORE
dy/dx = 2t/2t
But am not sure if I am correct, or if I am what do I do next?
Thanks