# Math Help - Sketch and find the area of the region bounded by the given curves. Choose the variab

1. ## Sketch and find the area of the region bounded by the given curves. Choose the variab

Sketch and find the area of the region bounded by the given curves. Choose the variable of integration so that the area is written as a single integral.

x = y2
x = 4

I am not sure where to start on this one.....If I could get some advice on how to graph this, that would be a great start. I have attached my attempt at graphing this.

2. ## Re: Sketch and find the area of the region bounded by the given curves. Choose the va

Your graph is missing the bottom half of the parabola. When you draw that, you should have a region to integrate. I think the variable of integration can be either x or y; you get a single integral either way.

- Hollywood

3. ## Re: Sketch and find the area of the region bounded by the given curves. Choose the va

Thanks Hollywood....

Would this graph work?

4. ## Re: Sketch and find the area of the region bounded by the given curves. Choose the va

You want something like:

5. ## Re: Sketch and find the area of the region bounded by the given curves. Choose the va

Here is my worked out solution. Look correct?

6. ## Re: Sketch and find the area of the region bounded by the given curves. Choose the va

Originally Posted by JDS

Here is my worked out solution. Look correct?
Yes it does.
But I did not do the actual calculations. Here they are.

7. ## Re: Sketch and find the area of the region bounded by the given curves. Choose the va

Originally Posted by MarkFL2
You want something like:

Or perhaps the OP wants the region bounded by his/her functions and the x-axis...

8. ## Re: Sketch and find the area of the region bounded by the given curves. Choose the va

Originally Posted by Prove It
Or perhaps the OP wants the region bounded by his/her functions and the x-axis...
Perhaps. I actually thought of that. But the actual post said, "Sketch and find the area of the region bounded by the given curves ..., $x = y^2$, $x = 4$", so I went with that.

- Hollywood