Find f'(x) if f(x)= arccot ((x+3)/ (x^2 +5))

Printable View

- Jan 17th 2013, 07:08 PMnancyaldapeHelp! Find f'(x) if f(x)= arccot ((x+3)/ (x^2 +5))
Find f'(x) if f(x)= arccot ((x+3)/ (x^2 +5))

- Jan 17th 2013, 07:19 PMMarkFLRe: Help! Find f'(x) if f(x)= arccot ((x+3)/ (x^2 +5))
Use

where

What do you find? - Jan 17th 2013, 07:38 PMnancyaldapeRe: Help! Find f'(x) if f(x)= arccot ((x+3)/ (x^2 +5))
F'(x)=( (-x^2 -6x +5)/(x^2 +5)^2 ) / ( 1 + ((x+3)/(x^2 +5))^2 ) ?

- Jan 17th 2013, 07:56 PMMarkFLRe: Help! Find f'(x) if f(x)= arccot ((x+3)/ (x^2 +5))
It appears you did not apply the negative sign in front of the derivative of the inverse cotangent function. Other than that, your result is correct, you just need to simplify by multiplying the result by:

- Jan 17th 2013, 09:34 PMProve ItRe: Help! Find f'(x) if f(x)= arccot ((x+3)/ (x^2 +5))